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Flattest Flashbet Contest! $100 in prizes!

TheBeliever 言った:

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80.00006 years ago

Wow, that's pretty awesome 😂

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400.51076 years ago

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0.120000006 years ago

RoyalDuck 言った:

The following algorithm will be used to determine the score of each entry:

abs(floor(rolls/(abs(profit)-0.000000001)*0.000000001))

I don't quite understand this algorithm, it could demonstrate an example or a better explanation.

Thanks

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4.1368886 years ago

Viguistam 言った:

I don't quite understand this algorithm, it could demonstrate an example or a better explanation.

Thanks

It's just meant to eliminate the guess work when dealing with close calls across different coins. I'll post some examples soon. For most cases, it will be very obvious who the winners are

Viguistam 言った:

I don't quite understand this algorithm, it could demonstrate an example or a better explanation.

Thanks

Here's some lua code that will hopefully illuminate its purpose.

function score(rolls,profit)

temp = rolls/math.abs(profit-0.000000001)*0.000000001

return math.floor(temp)

end

print(score(200,-0.000002))

print(score(30,0))

print(score(5000,-0.0000001))

print(score(4200,0))

print(score(42000,0.000000010))

result:

0

30

49

4200

4666

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101.25046 years ago

Thaynarar007 言った:

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101.25046 years ago

Sorry bro. That looks painful! Unfortunately, the goal for this contest is to get closest to 0 profit/loss, so that's definitely not gonna make the top 5

WILLAMUS36

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100.00006 years ago

willamus36

Soranith 言った:

Ok, THAT will be tough to beat!