Wow, that's pretty awesome 😂
The following algorithm will be used to determine the score of each entry:
abs(floor(rolls/(abs(profit)-0.000000001)*0.000000001))
I don't quite understand this algorithm, it could demonstrate an example or a better explanation.
Thanks
I don't quite understand this algorithm, it could demonstrate an example or a better explanation.
Thanks
It's just meant to eliminate the guess work when dealing with close calls across different coins. I'll post some examples soon. For most cases, it will be very obvious who the winners are
I don't quite understand this algorithm, it could demonstrate an example or a better explanation.
Thanks
Here's some lua code that will hopefully illuminate its purpose.
function score(rolls,profit)
temp = rolls/math.abs(profit-0.000000001)*0.000000001
return math.floor(temp)
end
print(score(200,-0.000002))
print(score(30,0))
print(score(5000,-0.0000001))
print(score(4200,0))
print(score(42000,0.000000010))
result:
0
30
49
4200
4666
Sorry bro. That looks painful! Unfortunately, the goal for this contest is to get closest to 0 profit/loss, so that's definitely not gonna make the top 5
WILLAMUS36
willamus36
Ok, THAT will be tough to beat!
