"House Edge" for Lottery?

Does my math check out?

There are 5 numbers of 1-36 (36 possible numbers)
And one bonus ball of 1-10 (10 possible numbers)

This means you have a 1 in 452 390 400 chance of winninng the jackpot.
Which means you would have to spend 45 239 040$ in order to cover every possible outcome and have 100% chance of winning.

In the same way, in a perfect world, 452 390 400 tickets will need to be sold before a ticket wins.

So for ever 452 390 400 tickets sold there "should" be 1 winner if each ticket was different.

So for every 45 239 040$ spent on tickets, duckdice is giving away 100 000$. Techinically profiting 45 139 040$ for every jackpot that is won.

That's a cool 45 239% house edge.

"technically" in a perfectly balanced mathematic world

i don't think your math checks out, when i asked the admins they had it at 1 in 3.3 million for jackpot hit but i can't break it down for you 'cos i'm a simpleton :) @doubleduck might be able to tell us how you went wrong in the maths

Well a breakdown of my math is as follows:

36 x 35 x 34 x 33 x 32 x 10 = 452 390 400 possible combinations.

I did however just read that the order of the numbers has an affect.
If no order is needed, then it increases the odds by 5x4x3x2x1 = 120x

So actually the new odds are 452 390 400 / 120 = 1 in 3 769 920

This is actually looking more logical, and a lot less ridiculous than my previous calculations.

Thanks @bobstone for making me dig a bit deeper.