Fermé :
Flattest Flashbet Contest! $100 in prizes!

TheBeliever a dit:

Dépôt
80.00006 years ago

Wow, that's pretty awesome 😂

  • 👍👎❤️😆😮😢🎉
  • Lien

Dépôt
400.51076 years ago

  • 👍👎❤️😆😮😢🎉
  • Lien

Dépôt
0.120000006 years ago

  • 👍👎❤️😆😮😢🎉
  • Lien

  • 👍👎❤️😆😮😢🎉
  • Lien
RoyalDuck a dit:

The following algorithm will be used to determine the score of each entry:

abs(floor(rolls/(abs(profit)-0.000000001)*0.000000001))

I don't quite understand this algorithm, it could demonstrate an example or a better explanation.

Thanks

  • 👍👎❤️😆😮😢🎉
  • Lien

  • 👍👎❤️😆😮😢🎉
  • Lien

Dépôt
4.1368886 years ago

  • 👍👎❤️😆😮😢🎉
  • Lien
Viguistam a dit:

I don't quite understand this algorithm, it could demonstrate an example or a better explanation.

Thanks

It's just meant to eliminate the guess work when dealing with close calls across different coins. I'll post some examples soon. For most cases, it will be very obvious who the winners are

  • 👍👎❤️😆😮😢🎉
  • Lien
Viguistam a dit:

I don't quite understand this algorithm, it could demonstrate an example or a better explanation.

Thanks

Here's some lua code that will hopefully illuminate its purpose.

function score(rolls,profit)

temp = rolls/math.abs(profit-0.000000001)*0.000000001

return math.floor(temp)

end

print(score(200,-0.000002))

print(score(30,0))

print(score(5000,-0.0000001))

print(score(4200,0))

print(score(42000,0.000000010))

result:

0

30

49

4200

4666

  • 👍👎❤️😆😮😢🎉
  • Lien

Dépôt
101.25046 years ago

  • 👍👎❤️😆😮😢🎉
  • Lien
Thaynarar007 a dit:

Dépôt
101.25046 years ago

Sorry bro. That looks painful! Unfortunately, the goal for this contest is to get closest to 0 profit/loss, so that's definitely not gonna make the top 5

  • 👍👎❤️😆😮😢🎉
  • Lien

WILLAMUS36

Dépôt
100.00006 years ago

  • 👍👎❤️😆😮😢🎉
  • Lien

willamus36

  • 👍👎❤️😆😮😢🎉
  • Lien

  • 👍👎❤️😆😮😢🎉
  • Lien
Soranith a dit:

Ok, THAT will be tough to beat!

  • 👍👎❤️😆😮😢🎉
  • Lien